I do have one question though if I may. I’m in the processing of porting over all my code into MySQLi prepared statements mainly for it’s security abilities but I’ve ran into a snag when trying to display multiple results on one page.

============= CODE =============
<?php

//Display numbers 1 – 20;

echo "”;
if($stmt->num_rows == NULL){
echo “No results found.”;
}else{
while($stmt->fetch()){

echo “”.$numbers.”";
}

}
echo “”;

?>
======== END CODE ============

Now, the above code works to display dynamic data stored in the db, but if I were to place another block of code, either the exact same fetch request or one requesting data from another table, both joined and not joined, under the first block of code, the results do not get displayed.

Why is this? I can do it using regular MySQL methods but not when using prepared statements.

Also, I’ve tried both keeping the stmt closed and open for testing purposes in each request block but still no luck.

How do I use a statement in this instance, the problem i seem to have is using the posted value inside the statement.
(also, I use a seperate file with the db connection in and include it when needed so there are no db connection details in the pages code)

thanks
Bob